# Statistic assignment help

1 A candy company claims that 24% of its plain candies are orange, and a sample of 200 such candies is randomly selected.

Find the mean and standard deviation for the number of orange candies in such groups of 200.

U = ________________

O = _________________

b. A random sample of 200 candies contains 34 orange candies. Is this result unusual? Does it seem that the claimed rate of 24% is wrong?

A.Yes, because 34 is within the range of usual values. Thus, the claimed rate of 24%

is probably wrong.

B.Yes, because 34 is greater than the maximum usual value. Thus, the claimed rate of 24%

is probably wrong.

C.Yes, because 34 is below the minimum usual value. Thus, the claimed rate of 24%

is probably wrong.

D.No, because 34 is within the range of usual values. Thus, the claimed rate of 24% is

not necessarily wrong.

2. If the random variable z is a Standard Normal Score, what is P(-2.00 ≤ z ≤ +2.00)? How did you find this probability?

Find the z-score for the standard normal distribution where:

P(z<+a) = 0.9625

3 Find the indicated z score. The graph depicts the standard normal distribution with mean 0 and standard deviation 1.

Z 0.8944 (A graph with a bell-shaped curve, divided into 2 regions by a line from top to bottom on the right side. The region left of the line is shaded and is labeled 0.8944. )

The indicated z score is ________________________(Round to two decimal places as needed.)

4. Assume that thermometer readings are normally distributed with a mean of 0degrees°C and a standard deviation of 1.00degrees°C. A thermometer is randomly selected and tested. For the case below, draw a sketch, and find the probability of the reading. (The given values are in Celsius degrees.)Between – 1.42 and 1.86

The probability of getting a reading between −1.42degrees°C and 1.86 degrees°C is __________________________

(Round to four decimal places as needed.)

5. Find the area of the shaded region. The graph to the right depicts IQ scores of adults, and those scores are normally distributed with a mean of 100 and a standard deviation of 15. (use chart above)

(A graph with a bell-shaped curve, divided into 3 regions by 2 lines from top to bottom, one on the left side and one on the right side. The region between the lines is shaded. Moving from left to right, the x-axis below the first line is labeled 80. The x-axis below the second line is labeled 105. )

The area of the shaded region is _______________ (Round to four decimal places as needed.)

6. A survey found that women’s heights are normally distributed with mean 62.4 in. and standard deviation 2.2 in. The survey also found that men’s heights are normally distributed with a mean 67.4 in. and standard deviation 2.8.

Complete parts a through c below.

a. Most of the live characters at an amusement park have height requirements with a minimum of 4 ft 8 in. and a maximum of 6 ft 2 in. Find the percentage of women meeting the height requirement.

The percentage of women who meet the height requirement is _____________%.

(Round to two decimal places as needed.)

b. Find the percentage of men meeting the height requirement.

The percentage of men who meet the height requirement is ________________%. (Round to two decimal places as needed.)

c. If the height requirements are changed to exclude only the tallest 5% of men and the shortest 5% of women, what are the new height requirements?

The new height requirements are at least ______________in. and at most ____________in.

(Round to one decimal place as needed.)

7. Complete the following statement.

If you are asked to find the 85th percentile, you are being asked to find _____.

Choose the correct answer below.

A. an area corresponding to a z-score of 0.85

B. a data value associated with an area of 0.85 to its left

C. a data value associated with an area of 0.85 to its right

D. an area corresponding to a z-score of minus−0.85

8 The population of current statistics students has ages with mean μ and standard deviation σ.

Samples of statistics students are randomly selected so that there are exactly 36 students in each sample. For each sample, the mean age is computed. What does the central limit theorem tell us about the distribution of those mean ages?

Choose the correct answer below.

A. Because n >30, the sampling distribution of the mean ages can be approximated by a normal distribution with mean μ and standard deviation σ.

B. Because n >30, the sampling distribution of the mean ages can be approximated by a normal distribution with mean μ and standard deviation (Fraction – sigma Over Root 36)

C Because n >30, the sampling distribution of the mean ages is precisely a normal distribution with mean μ and standard deviation (Fraction- sigma Over tRoot 36.)

D Because n>30, the central limit theorem does not apply in this situation.

9 Assume that women’s heights are normally distributed with a mean given by μ=63.4 in, and a standard deviation given by σ=1.9 in.

(a) If 1 woman is randomly selected, find the probability that her height is less than 64 in.

(b) If 37 women are randomly selected, find the probability that they have a mean height less than

64 in.

(a) The probability is approximately __________________(Round to four decimal places as needed.)

(b) The probability is approximately ___________________(Round to four decimal places as needed.)

10 A certain brand of candies have a mean weight of 0.8589 g and a standard deviation of 0.0512. A sample of these candies came from a package containing 466 candies, and the package label stated that the net weight is 397.7 g. (If every package has 466 candies, the mean weight of the candies must exceed 397.7/466 =0.8535g for the net contents to weigh at least 397.7 g.)

a. If 1 candy is randomly selected, find the probability that it weighs more than 0.8535 g.The probability is (Round to four decimal places as needed.)

b. If 466 candies are randomly selected, find the probability that their mean weight is at least 0.8535 g.

The probability that a sample of 466 candies will have a mean of 0.8535 g or greater is .(Round to four decimal places as needed.)

c. Given these results, does it seem that the candy company is providing consumers with the amount claimed on the label?

No or Yes), because the probability of getting a sample mean of 0.8535 g or greater when 466 candies are selected (is not ,is)exceptionally small.

11 The value given below is discrete. Use the continuity correction and describe the region of the normal distribution that corresponds to the indicated probability.

Probability of more than 8 passengers who do not show up for a flight

Choose the correct answer below.

A. The area between 7.5 and 8.5

B. The area to the left of 7.5

C. The area to the right of 7.5

D. The area to the left of 8.5

E. The area to the right of 8.5

12 Use a normal approximation to find the probability of the indicated number of voters. In this case, assume that 183 eligible voters aged 18-24 are randomly selected. Suppose a previous study showed that among eligible voters aged 18-24, 22% of them voted.

Probability that fewer than 46 voted

The probability that fewer than 46 of 183 eligible voters voted is ___________________

(Round to four decimal places as needed.)

## Needs help with similar assignment?

We are available 24x7 to deliver the best services and assignment ready within 3-4 hours? Order a custom-written, plagiarism-free paper

Get Answer Over WhatsApp Order Paper Now